AJAX 异步传输数据的问题

  要异步传输的数据:

  Xml代码

  ....

  <action xsi:type="basic:JavaScript" script="index += 1;"/>

  ....

  Ajax异步传输代码:

  Js代码

  

复制代码 代码如下:

  var postData = "input="+ escape(inputJSON) +"&script="+escape(xml)+

  "&feedGeneral=" + escape(feedGeneral);

  XmlHttpRequest.open("POST",url,true);

  XmlHttpRequest.setRequestHeader("Content-Type","application/x-www-form-urlencoded");

  XmlHttpRequest.send(postData);

  postData在encode和unencode,最终导致在后台Servlet中得到得到数据+被空格代替,使得script中的index += 1;变成了index = 1;从而导致后台Java代码在跑script出现死循环。

  在网上搜索,发现content-type使用application/x-www-form-urlencoded后:

  [来自http://www.w3.org/TR/html401/interact/forms.html#h-17.13.4.1]写道

  

复制代码 代码如下:

  Control names and values are escaped. Space characters are replaced by `+', and then reserved characters are escaped as

  described in [RFC1738], section 2.2: Non-alphanumeric characters are replaced by `%HH', a percent sign and two hexadecimal

  digits representing the ASCII code of the character. Line breaks are represented as "CR LF" pairs (i.e., `%0D%0A').

  然而使用form来提交方式来发起request却不会出现类似的问题,而form默认的Content-Type也是application/x-www-form-urlencoded:

  Js代码

  

复制代码 代码如下:

  $('test').innerHTML = "<form target='_blank' id='test_form' action='./gen_feed' method='post'>"

  + "<input type='text' name='input' /><input type='text' name='script' />"

  + "<input type='text' name='feedGeneral' /><input type='hidden' name='format' value='" + this.feed_type + "'

  />"

  + "<input type='submit' value='gen' /></form>";

  var test_form = $('test_form');

  test_form.elements[0].value = inputJSON;

  test_form.elements[1].value = script;

  test_form.elements[2].value = feedGeneral;

  test_form.submit();

  仍未发现问题到底出在何处,暂做备忘。暂时把script中的‘+'都用‘-'代替,index += 1;改成index -= -1;呵呵,以后有人看到这段自动生成的诡异脚本,不知道会作何感想,但现在也只能如此。