利用AJAX实现鼠标悬浮获取值的代码

  客户端代码mouseover.php

  

复制代码 代码如下:

  <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

  <html xmlns="http://www.w3.org/1999/xhtml">

  <head>

  <meta http-equiv="Content-Type" content="text/html; charset=gb2312" />

  <title>鼠标悬浮测试</title>

  </head>

  <script type="text/javascript" language="javascript">

  var xmlHttp;

  function createXMLHttpRequest(){

  if(window.ActiveXObject){

  xmlHttp = new ActiveXObject("microsoft.XMLHTTP");

  }

  else if(window.XMLHttpRequest){

  xmlHttp = new XMLHttpRequest();

  }

  }

  function sendRequest(t){

  var id = t.id

  createXMLHttpRequest();

  var url = "mouseover_check.php?page=" +t.id ;

  xmlHttp.onreadystatechange = callback;

  xmlHttp.open('GET',url,true);

  xmlHttp.send(null);

  }

  function callback(){

  if(xmlHttp.readyState == 4){

  if(xmlHttp.status == 200){

  document.getElementById("show").innerHTML = xmlHttp.responseText;

  }

  }

  }

  </script>

  <body>

  <p>

  <input type="text" value="here" id="1" onmouseover="sendRequest(this)" />

  </p>

  <p><br/>

  <input type="text" value="haha" id="2" onmouseover="sendRequest(this)" />

  </div>

  </p>

  <p></p>

  <span id="show"></span>

  </body>

  </html>

  服务器端代码:

  mouseover_check.php

  

复制代码 代码如下:

  <?php

  header("Content-type:text/html;charset=gb2312");

  header("cache-control:no-cache,must-revalidate");

  $name = $_GET['page'];

  if($name == '1'){

  echo "111";

  }

  else{

  echo "222";

  }

  ?>