jquery 利用show和hidden实现级联菜单示例代码

复制代码 代码如下:

  <%@ page language="java" contentType="text/html; charset=UTF-8"

  pageEncoding="UTF-8"%>

  <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

  <html>

  <head>

  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">

  <title>jqueryMenu</title>

  <script type="text/javascript" src="js/jquery-1.10.2.js"></script>

  <script type="text/javascript">

  $(document).ready(function(){

  var allMenu=$("ul > a");//找到所有主菜单

  allMenu.click(function(){

  var list=$(this).nextAll('li');//找到当前被点击a节点的所有li兄弟节点

  list.toggle('show');

  });

  });

  </script>

  </head>

  <body>

  <ul><a href="#">菜单一</a>

  <li><a href="#">子菜单一</a></li>

  <li><a href="#">子菜单二</a></li>

  </ul>

  <ul><a href="#">菜单二</a>

  <li><a href="#">子菜单一</a></li>

  <li><a href="#">子菜单二</a></li>

  </ul>

  </body>

  </html>