js跳转页面方法实现汇总

  

复制代码 代码如下:

  <span id="tiao">3</span><a href="javascript:countDown"></a>布丁足迹;秒后自动跳转……<meta http-equiv=refresh content=3;url='/search/billsearch.jsp'</ul>

  <!--脚本开始-->

  <script language="javascript" type="">

  function countDown(secs){

  tiao.innerText=secs;

  if(--secs>0)

  setTimeout("countDown("+secs+")",1000);

  }

  countDown(3);

  </script>

  <!--脚本结束-->

  按钮式:

  <INPUT name="pclog" type="button" value="GO" onClick="location.href='http://www.ddhbb.com/'">

  链接式:

  <a href="javascript:history.go(-1)">返回上一步</a>

  <a href="<%=Request.ServerVariables("HTTP_REFERER")%>">返回上一步</a>

  直接跳转式:

  <script>window.location.href='http://www.ddhbb.com';</script>

  开新窗口:

  <a href="javascript:" onClick="window.open('http://www.ddhbb.com/blog/guestbook.asp','','height=500,width=611,scrollbars=yes,status=yes')">布丁足迹</a>

  JS跳转页面参考代码

  第一种:

  <script language="javascript" type="text/javascript">

  window.location.href="login.jsp?backurl="+window.location.href;

  </script>

  第二种:

  <script language="javascript">

  alert("返回");

  window.history.back(-1);

  </script>

  第三种:

  <script language="javascript">

  window.navigate("top.jsp");

  </script>

  第四种:

  <script language="JavaScript">

  self.location='top.htm';

  </script>

  第五种:

  <script language="javascript">

  alert("非法访问!");

  top.location='xx.jsp';

  </script>

  =====javascript中弹出选择框跳转到其他页面=====

  <script language="javascript">

  <!--

  function logout()...{

  if (confirm("你确定要注销身份吗?是-选择确定,否-选择取消"))...{

  window.location.href="logout.asp?act=logout"

  }

  }

  -->

  </script>

  =====javascript中弹出提示框跳转到其他页面=====

  <script language="javascript">

  <!--

  function logout()...{

  alert("你确定要注销身份吗?");

  window.location.href="logout.asp?act=logout"

  }

  -->

  </script>

  [/code]