js 取时间差去掉周六周日实现代码

　　function GetDayNum(no,type) {

　　if (type == "35") {

　　var num7 = document.getElementById("6").value;

　　var value = document.getElementById("7").value;

　　var valueR = num7;

　　if (no == "7") {valueR = value;}//标识时间值

　　if (num7 != "" && value != "") {//两个时间段可以融合 BUG1

　　var numValue = 0;

　　var numValue = 0;

　　var day = 24 * 60 * 60 * 1000;

　　var dateArr = value.split("-");

　　var checkDate = new Date();

　　checkDate.setFullYear(dateArr[0], dateArr[1] - 1, dateArr[2]);

　　var checkTime = checkDate.getTime();

　　var dateArr2 = num7.split("-");

　　var checkDate2 = new Date();

　　checkDate2.setFullYear(dateArr2[0], dateArr2[1] - 1, dateArr2[2]);

　　var checkTime2 = checkDate2.getTime();

　　var numValue = (checkTime - checkTime2) / day; //相差的总天数

　　var totleWeek = numValue / 7; //差别多少周

　　var yuDay = numValue % 7; //除了整个星期的天数

　　var lastDay = 0;

　　var startWeek = num7.replace(/-/g, "/"); //把“-”改为“/”，其中“-”算时间不准确这个我测试了

　　//var date = new Date(parseInt(startWeek[0]), parseInt(startWeek[1]), parseInt(startWeek[2]));

　　var date = Date.parse(startWeek);

　　var dateNew = new Date(date);

　　var weekDay = dateNew.getDay(); //星期几

　　var endWeekDay = 0; //多余的天数有几天是周六或者周日

　　if ((weekDay == 6 && yuDay >= 2) || (weekDay == 7 && yuDay >= 1) || (weekDay == 5 && yuDay >= 3) || (weekDay == 4 && yuDay >= 4) || (weekDay == 3 && yuDay >= 5) || (weekDay == 2 && yuDay >= 6) || (weekDay == 1 && yuDay >= 7)) {

　　endWeekDay = 2;www.glzy8.com

　　}

　　if ((weekDay == 6 && yuDay < 1) || (weekDay == 7 && yuDay < 5) || (weekDay == 5 && yuDay < 2) || (weekDay == 4 && yuDay < 3) || (weekDay == 3 && yuDay < 4) || (weekDay == 2 && yuDay < 5) || (weekDay == 1 && yuDay < 6)) {

　　endWeekDay = 1;

　　}

　　// if (numValue == 0) { numValue = 1; }

　　numValue = numValue - (totleWeek * 2) - endWeekDay; //最终时间

　　}

　　}

　　}