Javascript下判断是否为闰年的Datetime包

  来看看源码:

  

复制代码 代码如下:

  /**

  * jscript.datetime package

  * This package contains utility functions for working with dates and times.

  */

  /*命名空间*/

  if (typeof jscript == 'undefined') {

  jscript = function() { }

  }

  jscript.datetime = function() { }

  /**

  * This function will return the number of days in a given month and year,

  * taking leap years into account.(这个函数返回所给某年、某月的天数,并且考虑了闰年的情况)

  *

  * @param inMonth The month, where January = 1 and December = 12.

  * @param inYear The year to check the month in.

  * @return The number of days in the specified month and year.

  */

  jscript.datetime.getNumberDaysInMonth = function(inMonth, inYear) {

  inMonth = inMonth - 1;

  var leap_year = this.isLeapYear(inYear);

  if (leap_year) {

  leap_year = 1;

  } else {

  leap_year = 0;

  }

  /*4, 6, 9, 11 月为 30 天,注意上面的 inMonth = inMonth - 1*/

  if (inMonth == 3 || inMonth == 5 || inMonth == 8 || inMonth == 10) {

  return 30;

  } else if (inMonth == 1) {/*2 月为 28 或者 29 天,视是否为闰年而定*/

  return 28 + leap_year;

  } else {/*其它月则为 31 天*/

  return 31;

  }

  } // End getNumberDaysInMonth().

  /**

  * This function will determine if a given year is a leap year.

  *(这个函数用来确定是否为闰年)

  * @param inYear The year to check.

  * @return True if inYear is a leap year, false if not.

  */

  jscript.datetime.isLeapYear = function(inYear) {

  if ((inYear % 4 == 0 && !(inYear % 100 == 0)) || inYear % 400 == 0) {

  return true;

  } else {

  return false;

  }

  } // End isLeapYear().