ajax传递一个参数具体实现

复制代码 代码如下:

  <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

  <html xmlns="http://www.w3.org/1999/xhtml">

  <head>

  <title></title>

  <script src="js/Jquery1.7.js" type="text/javascript"></script>

  <script type="text/javascript">

  $(function () {

  $('#txtUserName').blur(function () {

  $.ajax({

  type: "post",

  contentType: "application/json",

  url: "WebService1.asmx/ValidateUser",

  data: "{username:'" + $('#txtUserName').val() + "'}",

  success: function (result) {

  $('#spinfo').text(result.d);

  }

  })

  })

  })

  </script>

  </head>

  <body>

  <div>

  用户名<input type="text" id="txtUserName" /><span id="spinfo"></span><br />

  密码<input type="text" id="txtPwd" />

  </div>

  </body>

  </html>